What sum of money will produce rupees 70 as simple interest in 4 years at 3%?
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Home Books Audiobooks Documents Unfortunately, the footnote ends there, so there's not much in the way of detail about what these restrictions are or how long they'd remain in effect in a potential post-acquisition world. Given COD's continued non-appearance on Game Pass, you've got to imagine the restrictions are fairly significant if they're not an outright block on COD coming to the service. Either way, the simple fact that Microsoft is apparently willing to maintain any restrictions on its own ability to put first-party games on Game Pass is rather remarkable, given that making Game Pass more appealing is one of the reasons for its acquisition spree. The irony of Sony making deals like this one while fretting about COD's future on PlayStation probably isn't lost on Microsoft's lawyers, which is no doubt part of why they brought it up to the CMA. While it's absolutely reasonable to worry about a world in which more and more properties are concentrated in the hands of singular, giant megacorps, it does look a bit odd if you're complaining about losing access to games while stopping them from joining competing services. NCERT Exemplar Class 7 Maths Chapter 7 Comparing Quantities are part of NCERT Exemplar Class 7 Maths. Here we have given NCERT Exemplar Class 7 Maths Solutions Chapter 7 Comparing Quantities NCERT Exemplar Class 7 Maths Solutions Chapter 7 Comparing QuantitiesDirections: In questions 1 to 23, there are four options, out of which one is correct. Write the correct one. Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. S.P. = C.P. + Profit = 1800 + 216 = ₹ 2016 Question 11. Question 12. S.P. of buffalo = 44000 – 2200 = ₹ 41800 C.P. of cow = ₹ 18000 Profit % = 10% . ∴ S.P. of cow = 18000 + 1800 = ₹ 19800 Now, C.P. of both buffalo and cow = 44000 + 18000 = ₹ 62000 S.P. of both buffalo and cow = 41800+ 19800 = ₹ 61600 ∴ Loss = 62000 – 61600 = ₹ 400 Question 13. Thus, Raman’s income is 20% less than Mohan’s income. Question 14. Question 15. Amount = Principal + Interest = 3000 + 660 = ₹ 3660 Question 16. Question 17. Amount = 3000 + 900 = ₹ 3900 For Mohini : Principal = ₹ 4000, Rate = 10% p.a. Time \(=2 \frac{1}{2} \text { years }=\frac{5}{2}\) years Amount = 4000 + 1000 = ₹ 5000 ∴ Difference in amounts = 5000 – 3900 = ₹ 1100 Question 18. ⇒ x = 350 km Question 19. = ₹ 350 Question 20. Question 21. Question 22. (a) 75% (b) 50% (c) 40% (d) 60% Solution: (c) Total parts = 100 Unshaded parts = 40 ∴ Unshaded fraction \(=\frac{40}{100}=40 \%\) Question 23. (a) 36% (b) 64% (c) 27% (d) 48% Solution: (a) Total parts = 100 Shaded parts = 36 . ∴ Unshaded fraction \(=\frac{36}{100}=36 \%\) Directions: In each of the questions 24 to 59, fill in the blanks to make the statements true. Question 24. Question 25. Question 26. Question 27. Question 28. Question 29. Question 30. Question 31. Question 32. Question 33. Question 34. Question 35. ∴ Balance in Abida’s bank account = 1500 – 600 = ₹ 900 Question 36. Question 37. Question 38. Decrease percentage = 20% Now, new price of 1 kg sugar = 40 – 8 = ₹ 32 ∴ New price of 3 kg sugar = 32 × 3 = ₹ 96 Question 39. Question 40. Question 41. Question 42. Question 43. Thus, Aahuti should sell the house for ₹ 5355000 to make a profit of 5%. Question 44. Question 45. Question 46. Question 47. Question 48. Amount = Principal + Interest = 20000 + 800 = ₹ 20800 Question 49. Question 50. Question 51. Question 52. where T = Time period R% = Rate of interest and P = Principal Question 53. ∴ Difference = 504 – 336 = ₹ 168. Question 54. Question 55. Question 56. Sum of both interest = ₹ (180 + 240) = ₹ 420 Question 57. And 650% > 100% So, after converting 6.5 into percentage, the value of 6.5 is more than 100%. Directions: In questions 58 and 59, copy each number line. Fill in the blanks so that each mark on the number line is labelled with a per cent, a fraction and a decimal. Write all fractions in lowest terms. Question 58. Solution: Question 59. Solution: Directions: In questions 60 to 79, state whether the statements are True or False. Question 60. Question 61. Question 62. Question 63. Question 64. where P is the principal, R is the rate of interest and Tis the time. Question 65. Question 66. Question 67. Question 68. Question 69. Question 70. Question 71. Question 72. So, the cost price of the book is ₹ 55.5. Question 73. Question 74. Question 75. So, for earning again of 10% Sushma should have sold the watch for ₹ 3300 Question 76. Question 77. Now, amount = Principal + Interest = ₹ (800 + 288) = ₹ 1088 Question 78. For Rashmi : Principal = 6400, Rate = 15% p.a. Time = 5 years Required difference in interests = ₹ (4800 – 3360) = ₹ 1440 Question 79. Rotten lemons = 10% Number of remaining lemons which are not rotten = 720 – 72 = 648 S.P. of 720 lemons = ₹ (36 + 810) = ₹ 846 Here, C.P. > S.P. Therefore, there is a loss of ₹ (864 – 846) = ₹ 18 Question 80. Question 81. (a) Shade 25% of the grid. What is 25% of 300? Compare the two answers. (b) What is the value of 25 squares? (c) Shade 17% of the grid. What is 17% of 300? Compare the two answers. (d) What is the value of \(\frac{1}{10}\) of the grid? Solution: Now, each small square is worth 3 ∴ 25 small square worths 25 × 3 = 75 Both the values are same. (b) From part (a), value of 25 small squares is 75. Now, each small square is worth 3 ∴ 17 small square worths 17 × 3 = 51 Both the values are same. (d) Total numbers in grid = 10 × 10 = 100 ∴ \(\frac{1}{10} \text { of } 100=\frac{1}{10} \times 100=10\) Each small square is worth 3 ∴ 10 small square worths 10 × 3 = 30 Question 82. Question 83. Question 84. Question 85. Question 86. Question 87. Question 88. Question 89. Now calculate 52% of 700 using both the ways described above. Which way do you find easier? Solution: I : 52% of 700 = (1% of 700) × 52 = (0.01 × 700) × 52 = 7 × 52 = 364 We find that the way II is easier. Question 90. Question 91. Question 92. Question 93. Question 94. Question 95. Question 96. Question 97. Question 98. Question 99. Question 100. Question 101. ∴ Number of boys = 2000 – 800 = 1200 Question 102. Question 103. Mass of cement in mortar = 33% of 800 kg ∴ Mass of lime in mortar = [800 – (440 + 264)] kg = 96 kg Question 104. Question 105. Question 106. Question 107. II: Principal = ₹ (12000 – 4000) = ₹ 8000, Rate = 15%, Time = 3 years Total interest = ₹ (2160 + 3600) = ₹ 5760 Question 108. Question 109. So, the shopkeeper bought the chair at ₹ 1600. Question 110. So, amount of money invested by Dhruvika is ₹ 6750. Question 111. Question 112. Number of literate women = 40% of 6400 Question 113. Tax on tickets of 100 So, total tax collected from the programme = ₹ (40000 + 10000) = ₹ 50000 Question 114. New income – 20% of 50000 + 50000 = ₹ 60000 New spending amount = 40000 + 20% of 40000 = 40000 + 8000 = ₹ 48000 ∴ New savings of Bhavya = ₹ (60000 – 48000) = ₹ 12000 Question 115. Question 116. Manohar is a healthy 37 years old man whose blood pressure is in the normal category. (b) Systolic blood pressure of Manohar = 102 mm Hg ⇒ Diastolic blood pressure (c) Average systolic blood pressure in the prehypertension category Average diastolic blood pressure in the prehypertension category Question 117. Two children can be balanced on a Seesaw when \(\frac{\text { mass } 1}{\text { length } 2}=\frac{\text { mass } 2}{\text { length } 1}\) The child on the left and child on the right are balanced. What is the mass of the child on the right? (c) Life Science Application: A DNA model was built using the scale 2 cm : 0.0000001 mm. If the model of the DNA chain is 17 cm long, what is the length of the actual chain? Solution: (a) Let the length of the largest reticulated python – x cm According to question, 60% of x = 558 ⇒ x = 930 (b) We have, (c) Length of actual chain 0.0000001 mm is measured as 2 cm in the model. ∴ Length of actual chain when length of chain is 17 cm in the model \(=\frac{0.0000001}{2} \times 17=0.00000085 \mathrm{mm}\) Question 118. Find (a) The ratio of consonants to vowels in each of the terms. (b) The percentage of consonants in each of the terms. Solution: (a) (i) Number of consonants in Hypotenuse’ = 6 Number of vowels in ‘Hypotenuse’ = 4 (ii) Number of consonants in ‘Congruence’ = 6 Number of vowels in ‘Congruence’ = 4 (iii) Number of consonants in ‘Perpendicular’ = 8 Number of vowels in ‘Perpendicular = 5 (iv) Number of consonants in ‘Transversal’ = 8 Number of vowels in ‘Transversal’ = 3 (v) Number of consonants in ‘Correspondence’ = 9 Number of vowels in ‘Correspondence’ = 5 (b)(i) Percentage of consonants in ‘Hypotenuse’ (ii) Percentage of ‘consonants in Congruence’ (iii) Percentage of consonants in ‘Perpendicular’ (iv) Percentage of consonants in ‘Transversal’ (v) Percentage of consonants in ‘Correspondence’ Question 119. Therefore 6 out of every 10000 are defective T-shifts. Question 120. Question 121. Therefore correct unit price is ₹ 256. Question 122. Question 123. Question 124. Question 125. Value of the second and third scholarships = ₹ (20000 + 15000) = ₹ 35000 Now, value of the first scholarship = ₹ (60000 – 35000) = ₹ 25000 Question 126. Question 127. Question 128. Now, S.P. for Harish would be the C.P. for Archana. For Archana : C.P. = ₹ 945, Loss % = 20 Again, S.P. for Archana would be the C.P. for Babita. So, Babita got the gas-chullah for ₹ 756. Question 129. Solution: (i) → (E) (ii) → (H) (iii) → (O) (iv) → (J) (v) → (G) (vi) → (L) (vii) → (B) (viii) → (A) (ix) → (F) (x) → (K) (xi) → (D) (xii) → (I) Question 130. Question 131. Interest for second part So, the first part = ₹ 6000 And second apart = ₹ (10000 – 6000) = ₹ 4000 Question 132. Question 133. Question 134. Question 135. Question 136. Solution: (4) Calories that should come from proteins (5) Calories that may come from fat. Question 137. Number of students studying Maths ∴ Number of students studying both subjects = (93 + 102) – 150 = 45 Question 138. (a) What are the mean, median and mode of the areas listed? Since, n = 10 which is even Since, area = 310000 km2 occurs two times. ∴ Mode = 310000 km2 (b) Area of Gobi Desert = 1300000 km2 Area of Namib Desert = 310000 km2 Now, 1300000 = x × 310000 \(\Rightarrow \quad x=\frac{1300000}{310000}=4.19\) So, size of the Gobi Desert is 4.19 times the Namib Desert (c) Total number of Deserts = 10 Deserts listed in Asia = 5 (d) Total area of Deserts listed in Asia = 1300000 + 850000 + 320000+ 310000 + 260000 = 3040000 km2 Total area of all Deserts = 14350000 km2 Percentage of Deserts in Asia \(=\frac{3040000}{14350000} \times 100=21.1 \%\) Question 139. Question 140. What percentage of total has been coloured? (i) Red (R) = _______ (ii) Blue (B) = _______ (iii) Green (G) = _______ Check that the sum of all the percentages calculated above should be 100. If we rearrange the same pieces to form some other shape, will the percentatge of colours change? Solution: (i) Total traction for Red (R) ∴ Percentage of red colour = 37.5% (ii) Total fraction for Blue (B) ∴ Percentage of blue colour = 50% (iii) Total fraction for Green (G) ∴ Percentage of green colour = 12.5% Now, sum of all percentage = 37.5% + 50% +12.5% = 100% If we rearrange the same pieces to form some other shape, then percentage of colours will not change. We hope the NCERT Exemplar Class 7 Maths Chapter 7 Comparing Quantities will help you. If you have any query regarding NCERT Exemplar Class 7 Maths Solutions Chapter 7 Comparing Quantities, drop a comment below and we will get back to you at the earliest. What sum of money will produce rupees 143 as interest in 4 years at 5% simple interest?Answer : The sum of money will produce ₹143 as interest in 4 years at 5% simple interest is Rs. 715.
What sum of money will produce Rs 28600 as in interest in 3 years 3 months at 2.5% pa?28,600\], at the rate of \[2.5%\]p.a for the time of \[3\] years and 3 months. On solving this we get. So the principal amount will be \[Rs. 3,52,000\].
What sum of money will amount to Rs 3704.40 in 3 years at 5% compound interest?Using A = P(1 + r/100) n , we get 3704.40 = P(1 + 5/100) 3 => 370440/100 = P ×21/20×21/20×21/20 Or, P = 370440/100×20/21×20/21×20/21= 3200 Hence, required sum of money = Rs3200.
What sum of money would yield an interest of ₹ 36 in 3 years at 3% pa?Step-by-step explanation:
Hence the sum that would yield interest is 400.
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