For what value of k will the following equations have infinitely many solutions 2x 3y 7?

For what value of k will the following equations have infinitely many solutions 2x 3y 7?

Find the value of k for which each of the following systems of linear equations has an infinite number of solutions: 2x+3y=7, k 1x+k+2y=3k.

Solution

The given system may be written as2x+3y-7=0 (k−1)x+(k+2)y-3k=0 (adsbygoogle = window.adsbygoogle || []).push({}); The given system of equation is of the forma1x+b1y+c1 = 0a2x+b2y+c2 = 0Where, a1=2,b1=3,c1=−7a2=k,b2=k+2,c2=3kFor unique solution,we have (adsbygoogle = window.adsbygoogle || []).push({}); a1a2=b1b2=c1c2 2k−1=3k+2=−7−3k 2k−1=3k+2 and 3k+2=−7−3k ⇒2k+4=3k−3 and 9k=7k+14 ⇒k=7and k=7Therefore, the given system of equations will have infinitely many solutions, if k=7.

For what value of k will the following equations have infinite solutions 2x 3y 7?

Therefore, the given system of equations will have infinitely many solutions, if k=7.

For what value of K will have infinitely many solutions?

Hence, the given system of equations will have infinitely many solutions, if k=2.

For what value of k will the following equations have infinitely many solutions KX 3y

For what values of k will the following pair of linear equations have infinitely many solutions? kx + 3y - (k – 3) = 0. 12x + ky - k = 0. The value of k which satisfies both the equations is 6.

How do you know if there are infinitely many solutions to an equation?

Well, there is a simple way to know if your solution is infinite. An infinite solution has both sides equal. For example, 6x + 2y - 8 = 12x +4y - 16. If you simplify the equation using an infinite solutions formula or method, you'll get both sides equal, hence, it is an infinite solution.