What proportion of offspring from cc v cc would be cc?

If you do a punnet square of each trait, then multiply them together, you don't have to do the large confusing square. So there's a 50% for the offspring to exhibit trait A, 50% it will exhibit trait b, and 100% it will exhibit trait C, so it's 25% chance that the offspring will match parent 2.

Answer link

Meave60

Feb 17, 2018

#16/64#, or#25%#of their offspring are expected to have the same phenotype as parent 2.

Explanation:

Parent 2's phenotype is first trait dominant, second trait recessive, and third trait dominant.

#16/64#, or#25%#of their offspring are expected to have the same phenotype as parent 2. Their genotypes are#"AabbCC"#and#"AabbCc"#.

Answer link

Ms. Worth

Feb 17, 2018

There is one chance in four (25%) that an offspring will have the same phenotype as Parent 2

Explanation:

You figure out problems like this by doing it one allele at a time.
Write the proportions of each outcome as you go, then you can trace across to find the offspring you want.

1) Start with the aa × Aa cross
1/2 Aa#larr#50% Parent 2 phenotype
1/2 aa

2) Now do the Bb × bb cross
1/2 Bb
1/2 bb#larr#50% Parent 2 phenotype

3) Now do the Cc × CC cross
# {: ("1/2 CC"), ("1/2 Cc") :}} ##larr#100% Parent 2 phenotype

Now string the alleles together.
Like any other probability event, the chance that these phenotypes will occur simultaneously is the product of their individual odds.

Aa     bb     C _
 0.5 × 0.5 × 1.0   = 0.25

Answer:
There is one chance in four (25%) that an offspring will have the same phenotype as Parent 2

Check
The math here is so simple that it doesn't need a check.
All you'd really have to do is proofread it for typos.

But checking the concept might be something you'd want to do.

You can do the problem out manually and then count the total outcomes -vs- the outcomes that match parent 2.

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Hint: Zygosity is the extent where both copies of a chromosome or of a gene have the very same genome sequence. The diploid species is heterozygous in the genetic locus since its cells produce two distinct alleles (one wild-type allele and the other mutated allele) of a gene.

Complete answer:
The first parent genotype is AABBCC, so the possible gamete formed is only one type ABC, which is completely homozygous. The second parent is heterozygous for all the genes with genotype AaBbCc, so the possible gametes formed are Abc, ABc, aBc, aBC, abC, AbC, abc, ABC. Thus, only one offspring out of eight is completely heterozygous. Hence, the proportion of the offspring obtained from the cross AABBCC X AaBbCc is \[\frac{1}{8}\] for all the genes segregated independently.
 

So, the correct answer is option (A).

Additional information:
An organism is defined to be homozygous for a specific gene since the same alleles of the gene are represented on both homologous chromosomes. An individual who will be homozygous-dominant for a specific trait holds two copies of an allele that codes for a dominant trait. This allele is also referred to as the "dominant allele" Whenever the species is homozygous-dominant for a specific trait, the genotype of the species is depicted by a doubling of the symbol for that characteristic, such as "PP". A person who really is homozygous-recessive to a specific feature beheld two copies of the allele that will be encoded for the recessive trait. The genotype of a species that is homozygous-recessive to a specific feature is defined by a doubling of the relevant letter, like "pp".

Note: Heterozygous is a phenomenon wherein multiple variants of a single gene are being inherited from each one of the biological parents. The two distinct alleles associate with one another in a heterozygous genotype. This influences how the features are expressed. Diseases such as Huntington's disease, Marfan's syndrome, and hypercholesterolemia are linked with heterozygous gene variants.

What proportion of offspring should be Aabbcc and Aabbcc?

What proportion of the offspring would be heterozygous?

What proportion of the offspring will be homozygous for all three dominant traits?

How many genotypes can be predicted from a cross between Aabbcc and Aabbcc?