Which smallest natural number should divide 118 8th so that the quotient is a perfect cube?

Q. Check whether 24x3y2 is a perfect cube or not. If not, find the smallest number by which it should be divided to make it a perfect cube. Also, find the cube root of the perfect cube number so obtained.

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The smallest number with which 1188 should be divided to get a perfect cube is

Question

A

44

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B

54

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C

24

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Solution

The correct option is A 44By prime factorisation, 311883396313224422211 1188=3×3×3×2×2×11 =33×22×11 =33×44 If we divide the given number by 44, the resultant will be a perfect cube. 118844 = 27 = 33

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Which smallest natural number should divide 1188 so that the question is a perfect cube?

Thus, the required smallest number is 44.

IS 118 is a perfect cube?

If we look at the number 118, we know that the cube root is 4.904868131524, and since this is not a whole number, we also know that 118 is not a perfect cube.

Which is smallest natural number should divide 1188 so that the quotient is a perfect cube?

So, if we divide 1188 by 2 × 2 × 11 = 44, then the prime factorisation of the quotient will not contain 2 and 11. Hence the smallest natural number by which 1188 should be divided to make it a perfect cube is 44. And the resulting perfect cube is 1188 ÷ 44 = 27 (=33 ).

How do you find the smallest number to be divided to get a perfect cube?

Prime factorising 81, we get,.
We know, a perfect cube has multiples of 3 as powers of prime factors..
Here, number of 3's is 4..
So we need to divide the factorization by 3 to make 81 a perfect cube..
Hence, the smallest number by which 81 must be divided to obtain a perfect cube is 3..